Wednesday, January 25, 2012
Problem of the Week--January 30
Please help me. I would like to make a geometry bulletin board that has a border of circles, triangles and squares. I know that 20 shapes will fit across the board and that 12 shapes will fit down the board. If I start in the top left-hand corner with a circle, followed by a triangle, then a square, and repeat this pattern all around the board, how many of each shape will I need?
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21 comments:
You would need 64 shapes.
You should have 40 of each shape. Because 20 times 12 is 120 divided by 3 shapes is 40.
21 shapes each. I added 20 + 12 + 20 + 12 and then divided the answer by 3.
Darren fisher
you will need 20 of each shape
You would need 80 of each shape because since there will be 4 of the same shape and there are 20 rows going across 20x4=80.
3 x 20=60 x 2=120
3 x 12=36 x 2=72
120
+
72
___
182
3 x 20=60 x 2=120
3 x 12=36 x 2=72
120 + 72=182
If you went around the whole bulletin board you would get 20 of each shape.At first I thought there would be one less triangle then a circle and one less square then a triangle.When I got to the end I realizid why it may seem that way.It may seem like that because the circles start first and end farther from the beginning while the triangle and square sart second and last and end up closer to the beginning. Emma Peters
this is spencer you will need 240 shapes
Because they are both and even number and i proved it by doing it on paper that you will need 20 of each shape to create a boder and i figured out the primmeter by takeing the aross number and puting on the top and bottom and the down number adding that on both sides.
Emily McCown
The answer will be 20 shapes needed. I know this because I drew a picture by drawing the pattern and knowing how many shapes would fit across the board and how many would fit down the board.
I fugured howmany shapes make up the perimeter and divided it by 3 The answer 20 of each shape.
You will need 20 circles, triangles, and squares. I actually drew the table and I counted 20 of each. I also knew that it had to be at least 8 because there are 3 shapes and 12 go down 3 shapes
x 4
= 12 shapes across. so 4 will go down one side, 4 down the other side too so 4+4=8 shapes.
Matthew
I got the answer of sixty. I got this answer because there are 20across the top and 12 down the side so twenty times two is forty and the 10times two is 20 so I just have to add the forty and twenty and got sixty.Then to check I did 60divided by 3.
1. First I drew a rectangle and labeled how many shapes are on each side.
2. Second I drew the shapes around that rectangle
3. Third I counted how many of each shape there is.
4. Finally I checked my work
20 circles 20 triangles 20 rectangles
There are 21 circles, 20 squares, and 20 triangles. I found out by drawing a picture and counted each circle, triangle, and square.
(shapes will fit across) 20 x (shapes will fit down) 12 = 240.
(3 types of shapes repeat)
240/3 = 80, each shapes will need 80 times.
well if 20 can fit across then if you do 3x6 that equals 18 then plus two cicle, triangle so next is square. then if you do 3x3 then cicle tringle you get the twelve on that side. then square the 6x3 and end on cicle. next triangle , square and 3x3. which makes the coplete board so there are 21 of each shape not counting the cicle you start on and that is the answer. Meghan swantkowski
We will need 20 of each shape:
There is a total of 20 shapes across the top and bottom for a total of 40. There are 12 more shapes on the sides but 2 have already been used on each side making it 10 to add on each side for a total 20. Then I added 40 + 20= 60 and then i divided 60 by 3 to get 20 of each shape.
you will need 240 shapes
you will need 80 cicles 80 triangles and 80 sqaures. i got this by mutipling 20x12=240 then i divided 240 by 3 and it =80 and i did the border by doing circle,triangle, and sqaure by putting 20 across and and 12 down
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